Comment convertir une chaîne en fichier xml en java
<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><LoginResponse xmlns="http://tempuri.org/QuestIPhoneWebService/QuestIPhoneWebService"><LoginResult><RETURN_VALUE><ERROR RESULT= '-1' DESC = 'The password entered into the system is not valid. Please check your password and try again.'/></RETURN_VALUE></LoginResult></LoginResponse></soap:Body></soap:Envelope>
Salut, j'obtiens la valeur des webservices. Je veux convertir la chaîne ci-dessus en xml quelqu'un peut-il dire comment convertir la chaîne en fichier xml en java
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<LoginResponse xmlns="http://tempuri.org/QuestIPhoneWebService/QuestIPhoneWebService">
<LoginResult>
<ROOT xmlns:sql="urn:schemas-microsoft-com:xml-sql"><LOGIN_DETAILS USER_ID="testpub2" COMPANY_ID="1" USER_NAME=" aaa" SYSTEM_USER_ID="6976" USER_EMAIL_ID="[email protected]" TOKEN_STRING="A93805F1F1C340F5A8155FDD9B77E595" DISCLAIMER_AGREED="1" USER_ENABLED="1" USER_COMPANY_ENABLED="1" USER_TYPE="2" LOGIN_EXPIRY_DAYS="999" TOKEN_CREATION_DATE="2010-10-01T16:04:26" MOBILE_ENABLED="1" USER_COMPANY_MOBILE_ENABLED="1"/><COMPANY_DETAILS CLIENT_TYPE_ID="8"/><USER_SETTINGS><QUEST_GROUP ID="14293" NAME="World" ASSIGN_NUM="14"/><INDEX_PROVIDER ID="14251" NAME="QUEST (Default)"/><STOCK_IDENTIFIER ID="57" NAME="TICKER"/></USER_SETTINGS><PERMISSIONS><QUEST_FUNCTIONS><FUNCTION NAME="charting" ID="501" ACCESS="1"/><FUNCTION NAME="modeller" ID="512" ACCESS="1"/><FUNCTION NAME="momentum" ID="513" ACCESS="1"/><FUNCTION NAME="portfolio" ID="516" ACCESS="1"/><FUNCTION NAME="search" ID="518" ACCESS="1"/><FUNCTION NAME="sensitivity" ID="521" ACCESS="1"/><FUNCTION NAME="statistics" ID="524" ACCESS="1"/><FUNCTION NAME="strategy" ID="525" ACCESS="1"/><FUNCTION NAME="summary" ID="526" ACCESS="1"/><FUNCTION NAME="triangle" ID="528" ACCESS="1"/><FUNCTION NAME="valuation" ID="529" ACCESS="1"/><FUNCTION NAME="commentary" ID="530" ACCESS="1"/><FUNCTION NAME="CITN" ID="534" ACCESS="1"/><FUNCTION NAME="batch report" ID="553" ACCESS="1"/><FUNCTION NAME="ModellerWS" ID="557" ACCESS="1"/><FUNCTION NAME="Sector Analysis" ID="562" ACCESS="1"/></QUEST_FUNCTIONS><ADMIN_FUNCTIONS><FUNCTION NAME="administrator" ID="531" ACCESS="0"/><FUNCTION NAME="author" ID="532" ACCESS="1"/><FUNCTION NAME="publisher" ID="533" ACCESS="0"/><FUNCTION NAME="editor" ID="539" ACCESS="0"/></ADMIN_FUNCTIONS></PERMISSIONS></ROOT>
10-04 14:30:08.696: DEBUG/login result is(439): </LoginResult></LoginResponse></soap:Body></soap:Envelope>
Le nœud enfant vient comme ceci USER_ID= "testpub2" Je dois convertir xnode et obtenir la valeur comment covert xml node? et prenez la valeur en utilisant saxparser. est-ce que je peux prendre la valeur directement?
11
2 answers
Le code ci-dessous convertit une chaîne en un document XML. Une fois que vous avez le document, vous pouvez naviguer dans les nœuds ou vous pouvez écrire dans un fichier, etc.
import java.io.*;
import javax.xml.parsers.*;
import org.w3c.dom.*;
import org.xml.sax.*;
public class Util {
public static Document stringToDom(String xmlSource)
throws SAXException, ParserConfigurationException, IOException {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
return builder.parse(new InputSource(new StringReader(xmlSource)));
}
}
32
Author: Suresh Kumar, 2010-10-08 06:30:59
public void writeFile(String yourXML){
BufferedWriter out = new BufferedWriter(new FileWriter("outfilename.xml"));
try {
out.write(yourXML);
} catch (IOException e) {
e.printStackTrace();
} finally {
out.close();
}
}
0
Author: amra, 2015-03-01 15:01:36